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A man of height H is standing in front of an inclined plane mirror at an angle `theta` from horizontal. The vertical separation between man and inclined plane is x. Man can see its complete image in length `(H(H+x)"sin"theta)/(H +2x)` of mirror . (Given : x = H = 1m and `theta = 45^(@)`) If man starts moving with velocity `1 ms^(-1)` along vertical, find out length of mirror at t = 1s in which he can see his complete image.A. `(3)/(10)m`B. `(3sqrt(2))/(5)m`C. `(3)/(5sqrt(2))`D. `(3)/(5)`m |
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Answer» Correct Answer - C In this case only x will change so required length of mirror =`(1(1+2)"sin"45^(@))/(1+2xx2)` =`(3 xx (1)/(sqrt(2)))/(5) = (3)/(5sqrt(2))m` |
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