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A man of mass M standing at a height hfrom the floor in a gravity free space throws a ball of mass m straight down with a speed u. When the ball reaches the floor, find the distance of the man above the floor. |
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Answer» Solution :When the man throws the ball with VELOCITY u, he recoils with velocity V. `MU=MV`  `V=(mu)/M` Time taken by the ball to REACH the ground `t=h/u` Distance moved by man in this time `t=v.t =(mu)/M. h/u =m/M.h` HEIGHT of man at the time the ball strikes the ground is `H =h +m/M h, H=h (1+m/M)` |
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