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A man sees the bottom and top of a building at a depression of 50° and 35° respectively from the top of a 40m high tower.a) Draw a rough figure using the given data.b)Find the distance from tower to building.c)Find the height of building.[tan 50°=1.1918,tan 35°=0.7002]No need of irrelevant answers.... |
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Answer» GIVEN : A MAN SEES the bottom and TOP of a building at a depression of 50° and 35° respectively from the top of a 40m high tower. [TAN 50°=1.1918,tan 35°=0.7002] To Find : a) Draw a rough figure using the given data. b)Find the distance from tower to building. c)Find the height of building. Solution: Height of building = a m Height of tower above building = 40- a m Horizontal Distance between tower and building. = d m man sees the bottom at a depression of 50° Angle of Depression = angle of elevation Tan50° = Height of Tower / Horizontal Distance between tower and building. => 1.1918 = 40 / d => d = 33.5627 m Horizontal Distance between tower and building. = 33.5627 m Tan35° = Height of tower above building / Horizontal Distance between tower and building. => 0.7002 = (40 - a) / 33.5627 => 23.5 = 40-a => a = 16.5 m height of building. = 16.5 m Learn more: From a point on the ground, the angles of elevation of the bottom ... The angles of elevation of the top of a lighthouse from 3 boats A , B ... |
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