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A man squatting on the ground gets straight up and stand. The force of reaction of ground on the man during the process is.A. constant and equal to `mg` in magnitudeB. constant and greater than `mg` in magnitudeC. variable but always greater than `mg`.D. at first greater than `mg`, and later becomes equal to `mg`. |
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Answer» Correct Answer - D When the man is squatting on the ground he is tilted somewhat, hence he also has to balance frictional force besides his weight in this case. `R =` reactional force = friction + mg `rArr R gt mg` When the man gets straight up in that case friction `= 0` `rArr "Reactional force" = mg`. |
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