1.

A man standing symertrically between parallel cliffs,claps his hands and hearing a series of echoes at intervals of s if speed of sound in air is 340 m/s then the distance between two parallel cliffs is :

Answer»

340 m
510 m
680 m
270 m .

Solution :here `(2x)/(v) = 1 ` SEC
x= `(v)/(2) = (340)/(2) = 170 `m.
`THEREFORE` distance between two CLIFFS = `2XX 170 = 340 `m.
Hence the correct CHOICE is (a).


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