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InterviewSolution
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A man throws a die until he gets a number greater than `3`. The probability that he gets `5` in the last throwA. `1//3`B. `1//4`C. `1//6`D. `1//36` |
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Answer» Correct Answer - A `(a)` At event `A` he gets a number greater than `3` `:.P(A)=1//2` At event `B` he gets `5` in last throw `:.P(B)=1//6` `:.` Required probability is `P(E)=(1)/(6)+(1)/(2)*(1)/(6)+(1)/(2)*(1)/(2)*(1)/(6)+…..oo` `=((1)/(6))/(1-(1)/(2))=(1)/(3)` |
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