1.

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 second. What should be the speed of the throw so that two balls are in the sky at any time?

Answer»

At least 9.8 `m//s`
Any speed less than `19.6m//s`
Only with speed `19.6 m//s`
More than `19.6 m//s`

SOLUTION :For more than 2 BALLS to be in the air, the time interval should be t>(2+2)s or 4 s.
The maximum time of flight for each ball is `=(2u)/(g)`
THUS `(2u)/(g)` >4 s or U > 2g
Bur g=9.8 `ms^(-2)`
`:. ` u> 19.6 `ms^(-1)`


Discussion

No Comment Found

Related InterviewSolutions