A Man Traveled From The Village To The Post-office At The Rate Of 25

1.	A Man Traveled From The Village To The Post-office At The Rate Of 25 Kmph And Walked Back At The Rate Of 4 Kmph. If The Whole Journey Took 5 Hours 48 Minutes, Find The Distance Of The Post-office From The Village?
Answer» Average SPEED = (2ab)/(a + b) here a = 25 b = 4 Average speed = 225 4/(25 + 4) = 200/29 kmph. Distance COVERED in 5 HOURS 48 minutes = Speed * time Distance = (200/29)(29/5) = 40 kms Distance covered in 5 hours 48 minutes = 40 kms Distance of the post office from the village = (40/2) =20 km. Average speed = (2ab)/(a + b) here a = 25 b = 4 Average speed = 225 * 4/(25 + 4) = 200/29 kmph. Distance covered in 5 hours 48 minutes = Speed * time Distance = (200/29)*(29/5) = 40 kms Distance covered in 5 hours 48 minutes = 40 kms Distance of the post office from the village = (40/2) =20 km.

A Man Traveled From The Village To The Post-office At The Rate Of 25 Kmph And Walked Back At The Rate Of 4 Kmph. If The Whole Journey Took 5 Hours 48 Minutes, Find The Distance Of The Post-office From The Village?

Answer»

Average SPEED = (2*a*b)/(a + b) here a = 25 b = 4

Average speed = 2*25 * 4/(25 + 4) = 200/29 kmph.

Distance COVERED in 5 HOURS 48 minutes = Speed * time

Distance = (200/29)*(29/5) = 40 kms

Distance covered in 5 hours 48 minutes = 40 kms

Distance of the post office from the village = (40/2) =20 km.

Average speed = (2*a*b)/(a + b) here a = 25 b = 4

Average speed = 2*25 * 4/(25 + 4) = 200/29 kmph.

Distance covered in 5 hours 48 minutes = Speed * time

Distance = (200/29)*(29/5) = 40 kms

Distance covered in 5 hours 48 minutes = 40 kms

Distance of the post office from the village = (40/2) =20 km.

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