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A man walk at a speed of 1m/s and covers a certain distance in some time. But, if he walks at a seed of 3m/s, he covers an additional distance of 15 m in the same time. What is the distance he actually covered? Why? How? |
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Answer» Let Distance=D; Speed= S and Time=TIn this CASE, Time T is the same.Distance = Speed x Time or D= SxTIn the FIRST case, D = 1 xT or D =T ——->(1)In the SECOND case, D + 15 = 3 xT or 3 T ——->(2)Using value of D as per (1) in (2),T +15 = 3 T or 2T =15 or T=15/2= 7.5 secondsAs D=S x T, Distance covered in first case = 1m/second x 7.5 second= 7.5 METERS(Also, Distance covered in 2nd case = 7.5 + 15 = 22.5 mteres) MARK me brainliest |
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