1.

A man weighing 60 kg is standing on a trolley weighing 240 kg. The trolley is resting on a frictionless horizonral rails. If the man starts walking on the trolley with a constant speed of 1 ms^(-1) then after 4 second. The displacement of the man relative to the ground is :

Answer»

4.2 m
4.8 m
3.2 m
3 m

Solution :ACCORDING to law of conservation of momentum
`60 xx 1 = (60+ 240) upsilon` or `upsilon= 0.2 MS^(-1)`
Resultant speed of man `= (1 -0.2) = 0.8 ms^(-10)`
Now `S = UT = 0.8 xx 4 = 3.2 m`
(c) is the CHOICE.


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