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A man weighing `60kg` `f` suports a body of `20kg f ` on his head. Calculate work done by him in moving a distance of `15m` up an incline of `1` in 10 . Take `g=9.8m//s^(2)` |
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Answer» Here, `m=60kg+20kg=80kg` `W=?s=15m, sintheta=(1)/(10),g=9.8ms^(2)` `W=(mgsintheta)s=80xx9.8xx(1)/(10)xx15` |
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