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A man weighs 50 kg at earth'ssurface. At what height above the earth's surface his weight becomes half (Radius of earth = 6400 km) : |
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Answer» 2526 km or `(R^(2))/((R+H)^(2))=(1)/(2) rArr (R )/(R+h)=(1)/(sqrt(2))` `therefore sqrt(2)R=R+h` `h=(sqrt(2)-1)R=0.414xx6400=2650` km. Thus CORRECT CHOICE is (c ). |
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