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A manstanding. Observesrainfallingwithvelocityof20m//satanangleof 30^@withthe verticalfind outvelocityof manso thatrainappearsto fallvertically |
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Answer» Solution :` vecV_(R)=- 10hati- 10sqrt(3) hatj` ` vecV_m=-v_xhati` ` vecV_(RM)=- (10- v_x) HATI - 10 sqrt(3) hatj ` Anglewiththevertical`=30^@` ` impliestan30^@=( 10 -v_s )/( - 10sqrt(3)) impliesv_x= 20 m//s`
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