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A manufacturing plant earned \$80$80dollar sign, 80 per a man-hour of labor when it opened. Each year, the plant earns an additional 6\%6%6, percent per man-hour.Which expression gives the amount the plant earned per a man-hour of labor 333 years after it opened?Choose 1 answer:Choose 1 answer:(Choice A)A80(1+0.06)(1+0.06)(1+0.06)80(1+0.06)(1+0.06)(1+0.06)80, left parenthesis, 1, plus, 0, point, 06, right parenthesis, left parenthesis, 1, plus, 0, point, 06, right parenthesis, left parenthesis, 1, plus, 0, point, 06, right parenthesis(Choice B)B80+0.06\cdot 0.06\cdot 0.0680+0.06⋅0.06⋅0.0680, plus, 0, point, 06, dot, 0, point, 06, dot, 0, point, 06(Choice C)C80\cdot 0.06\cdot 0.06\cdot 0.0680⋅0.06⋅0.06⋅0.0680, dot, 0, point, 06, dot, 0, point, 06, dot, 0, point, 06(Choice D)D80+(1+0.06)(1+0.06)(1+0.06)80+(1+0.06)(1+0.06)(1+0.06) |
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Answer» Answer: A(t)= 80 (1.05)^t Step-by-step explanation: Step-by-step explanation: earning an additional 5% means the MANUFACTURING plant KEEPS the original 100% and EARS 5% more for a total of 105%. So each year, the AMOUNT the plant earns per man-hour is multiplied by 105%, which is the same as a factor of 1.05. If we start with the initial amount, $80, that the plant earned per man-hour, and keep multiplying by 1.05, this function gives us the amount A(t) that the plant earns per man-hour t years after it opens: A(t) =80* 1.05^t. |
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