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A mapping f: R → R defined by f (x) = ex where x ∈ R is (a) one-one onto (b) one-one into (c) many-one into (d) many-one into |
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Answer» Answer: (b) one - one into For all x1, x2 ∈ R, f (x1) = f (x2) ⇒ ex1 = ex2 ⇒ x1 = x2 ⇒ f is one-one. Let y = f (x) = ex ⇒ x = loge y Now x is not defined for y < 0 ∴ y ∈ R does not have a pre-image in R when y is negative. ∴ f is into. |
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