1.

A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is:

Answer»

0.01
0.02
0.03
0.06

Solution :Here applying `nu= U + at`
`0 = 6 + AXX 10:. a =-0.6 MS^(-2)`
Also `mu mg = ma` or`mu=(a)/(g) =( 0.6)/(10) = 0.06`
HENCE choice is (d).


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