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A marble block of mass 2 kg lying on ice when given a velocity of 6 m//s is stopped by friction in 10 s. Then the coefficient of friction is: |
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Answer» 0.01 `0 = 6 + AXX 10:. a =-0.6 MS^(-2)` Also `mu mg = ma` or`mu=(a)/(g) =( 0.6)/(10) = 0.06` HENCE choice is (d). |
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