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A marble going at a speed of `2 ms^(-1)` hits another marble of equal mass at rest. If the collision is perfectly elastic, then the velocity of the first marble after collision isA. `4 ms^(-1)`B. `0 ms^(-1)`C. `2 ms^(-1)`D. `3 ms^(-1)` |
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Answer» Correct Answer - B `vecv_(1)=((m_(1)-m_(2))/(m_(1)+m_(2)))vecu_(1)+((2m_(2))/(m_(1)+m_(2))) vecu_(2)`. |
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