A mason has to fit a bathroom with square marble tiles of the largest

1.	A mason has to fit a bathroom with square marble tiles of the largest possible size. The size of the bathroom is 10 ft. by 8 ft. What would be the size in inches of the tile required that has to be cut and how many such tiles are required?
Answer» Given: The size of the bathroom is 10 ft. by 8 ft. To find: the size in inches of the tile required that has to be cut and how many such tiles are required? Solution: To find the largest size of tile, we should find HCF of 10 and 8 Prime factors of 10 = 2 × 5 Prime factors of 8 = 2 × 2 × 2 Therefore HCF of 10 and 8 is: 2 ft Since i ft = 12 inches Therefore the largest size of tile is: 2 × 12 inches = 24 inches Area of bathroom = length of bathroom × breadth of bathroom = 10 × 8 = 80 sq. ft Area of 1 tile = length of tile × breadth of tile = 2 × 2 = 4 sq. ft Number of tiles = \(\frac{area\,of\,bathroom}{area\,of\,one\,tile}\) = \(\frac{80}{4}\) = 20 tiles NOTE: Always find the HCF of the given values to find their maximum.

A mason has to fit a bathroom with square marble tiles of the largest possible size. The size of the bathroom is 10 ft. by 8 ft. What would be the size in inches of the tile required that has to be cut and how many such tiles are required?

Answer»

Given:

The size of the bathroom is 10 ft. by 8 ft.

To find:

the size in inches of the tile required that has to be cut and how many such tiles are required?

Solution:

To find the largest size of tile, we should find HCF of 10 and 8

Prime factors of 10 = 2 × 5

Prime factors of 8 = 2 × 2 × 2

Therefore HCF of 10 and 8 is: 2 ft

Since i ft = 12 inches

Therefore the largest size of tile is:

2 × 12 inches = 24 inches

Area of bathroom = length of bathroom × breadth of bathroom

= 10 × 8

= 80 sq. ft

Area of 1 tile = length of tile × breadth of tile

= 2 × 2

= 4 sq. ft

Number of tiles = \(\frac{area\,of\,bathroom}{area\,of\,one\,tile}\)

= \(\frac{80}{4}\)

= 20 tiles

NOTE:

Always find the HCF of the given values to find their maximum.