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A mass 1 kg is suspended by a thread. It is (i) lifted up with an acceleration `4.9m//s^(2)` (ii) lowered with an acceleration `4.9m//s^(2)`. The ratio of the tensions isA. `1 : 3`B. `3 : 1`C. `1 : 1`D. `1 : sqrt(5)` |
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Answer» Correct Answer - B `T_(1)- mg = ma" "mg-T_(2)= ma` `T_(1)=m(g+a)" "T_(2)=m(g-a)` `T_(1)/T_(2)=(g+a)/(g-a)=14.7/4.9=3/1` |
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