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A mass 2 kg describes a circle of radius 1 m on a smooth horizontal table at a uniform speed .If is joined to the centre of the circle by a string, which can just withstand 32 N, then the greatest number of revolution per minute , perfomed by the mass would beA. 38B. 4C. 76D. 16 |
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Answer» Correct Answer - A `T=mr omega^(2)=m r 4 pi ^(2)n^(2)` ` therefore n=sqrt((T)/(mr4pi^(2)))=sqrt(((2xx16))/(2xx1xx4xx10))` `=(2)/(sqrt10)rps` `=(120)/(3.16)=38rpm`. |
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