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A mass 2 kg is whirled in a horizontal circle by means of a string at an initial speed of 5 revolutions per minute . Keeping the radius constant the tension in the string is doubled. The new speed is nearlyA. 14 rpmB. 10 rpmC. 2.25 rpmD. 7 rpm |
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Answer» Correct Answer - D Tension In the string `T=m omegaa ^(2) r=4pi^(2)n^(2)` mr `therefore T alpha n^(2)implies(n_(2))/(n_(1))=sqrt((T_(2))/(T_(1)))impliesn_(2)=5sqrt((2T)/(T))=7"rpm"`. |
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