A mass hangs at theend of a massless spring and oscillates up and down at its natural frequency f. If the spring is cut at the midpoint and and mass reattached at the end, the frequency of oscillation is :

A mass hangs at theend of a massless spring and oscillates up and down

1.	A mass hangs at theend of a massless spring and oscillates up and down at its natural frequency f. If the spring is cut at the midpoint and and mass reattached at the end, the frequency of oscillation is :
Answer» `sqrt(2)f` `2sqrt(2)` `f//2` `f sqrt(2)`. Solution :Frequency of oscillation ofspring is given by `v=(1)/(2PI) sqrt((K)/(m))` Since spring is cut into EQUAL parts `:.` spring constant becomes two times and hence frequency becomes `sqrt(2)` times So correct choice is a.

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A mass hangs at theend of a massless spring and oscillates up and down at its natural frequency f. If the spring is cut at the midpoint and and mass reattached at the end, the frequency of oscillation is :

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