1.

A mass m is suspended from a spring of force constant k and just touches another idential spring fixed to the floras shown in the figure. The time period of small oscillation is

Answer»

`2pi SQRT((m)/(k))`
`PI sqrt((m)/(k)) + pi sqrt((m)/(k//2))`
`pi sqrt((m)/(3k//2))`
`pi sqrt((m)/(k)) + pi sqrt((m)/(2k))`

Solution :When .m. MOVES slightly DOWNWARD, then both spring are EFFECTING for half period
`t_(1) = pi sqrt((m)/(2k))`
when mass moves upwards only
Upper spring is effective
`t_(2) = pi sqrt((m)/(k))`
`:.` Time period `T = t_(1) + t_(2)`
`T = pi sqrt((m)/(2k)) + pi sqrt((m)/(k))`


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