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A mass m is suspended from a spring of length l and force constant K . The frequency of vibration of the mass is `f_(1)`. The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is `f_(2)` . Which of the following relations between the frequencies is correctA. `f_(1) = sqrt2 f_(2)`B. `f_(1) = f_(2)`C. `f_(1) = 2f_(2)`D. `f_(2) = sqrt2 f_(1)` |
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Answer» Correct Answer - D |
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