InterviewSolution
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InterviewSolution
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A mass (M) is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes `(5T)/3`. Then the ratio of `m/M` is .A. `3/5`B. `25/9`C. `16/9`D. `5/3` |
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Answer» Correct Answer - C `T = 2pisqrt((M)/(k))` and `(5T)/(3) = 2pisqrt((M + m)/(k))` On driving ` = (5T)/(3T) = sqrt((M + m)/(M))` `rArr (25)/(9) = (M + m)/(M) rArr (m)/(M) = (16)/(9)` |
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