A mass m is suspendedto a spring of length Land force constant k. The frequency of vibration isv. The spring is cut into two equal parts and each half is loaded with same mass m. The new frequency v' is given by :

A mass m is suspendedto a spring of length Land force constant k. The

1.	A mass m is suspendedto a spring of length Land force constant k. The frequency of vibration isv. The spring is cut into two equal parts and each half is loaded with same mass m. The new frequency v' is given by :
Answer» `v'=SQRT(2)v` `v'=(v)/(sqrt(2))` `v'=2v` `v'=4v`. Solution :FREQUENCY of LOADED spring is `v=(1)/(2pi)sqrt((k)/(m))`. When spring is cut into two equal then spring constant of each part becomes `k.=2k` `:.""v.=(1)/(2pi)sqrt((k.)/(m))` `:.""(v.)/(v)=sqrt(2)IMPLIES""v.=sqrt(2)v` Thus correct choice is (a).

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A mass m is suspendedto a spring of length Land force constant k. The frequency of vibration isv. The spring is cut into two equal parts and each half is loaded with same mass m. The new frequency v' is given by :

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