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A mass m on the surface of the Earth is shifted to atarget equal to the radius of the Earth. If R is the radius and M is the mass of the Earth, then work done in this process is |
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Answer» `(mgR)/2` `U_(T)=(-GMm)/(2R)` `W=U_(T)-U_(E)=(-GMm)/(2R)+(GMm)/R` = `(GMm)/(2R)=(GR^(2)m)/(2R)=(mgR)/2` |
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