InterviewSolution
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InterviewSolution
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A mass m starting from A reaches B of a frictionless track. On reaching B, it pushes the track with a force equal to x times its weight, then the applicable relation is A. (a) `h=((x+5))/(2)r`B. (b) `h=x/2r`C. (c) `h=r`D. (d) `h=((x+1)/(2))r` |
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Answer» Correct Answer - A KE of blocks at `B=PE` at `A-PE` at B `1/2mv^2=mgh-mg2r=mg(h-2r)` `v^2=2g(h-2r)` (i) Also, `(mv^2)/(r)=xmg+mg` or `v^2=(x+1)rg` (ii) Equating Eqs (i) and (ii), we get `2g(h-2r)=(x+1)gr` or `2gh=(x+1)gr+4gr=(x+5)gr` `h=((x+5)/(2))r` |
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