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A mass of `1 kg` attached to the bottom of a spring has a certain frequency of vibration. The following mass has to be added to it in order to reduce the frequency by half :A. `1 kg`B. `2 kg`C. `3 kg`D. `4 kg` |
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Answer» Correct Answer - C `f_(1) = (1)/(2pi)sqrt((K)/(m_(1)))` `f_(2) = (1)/(2pi)sqrt((K)/(m_(2)))` `f_(2) = (f_(1))/(2)` or `m_(2) = 4m_(1)` or `m_(2) - m_(1) = kg` |
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