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A mass of 1 kg is suspended by means of a thread. The system is (i) lifted up with an acceleration of 4.9 ms^(-2) (ii) lowered with an acceleration of 4.9 ms^(- 2). The ratio of tension in the first and second case is |
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Answer» `3:1` Using Newton.s SECOND LAW of motion, `T_(1)` - mg= ma `T_(1)=m(g+a)` …(i) Case-II Using Newton.s second law of motion, `mg-T_(2)=ma` `T_(2)=m(g-a)` …(ii) From EQN. (i) and (ii) `(T_(1))/(T_(2))=(g+a)/(g-a)=(9.8+4.9)/(9.8-4.9)=3/1` 
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