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A mass of 1kg attached to one end of a string is first lifted up with acceleration 4.9m//s^2 and then lowered with same acceleration. What is the ratio of tension in string in two cases |
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Answer» Solution :When MASS is lifted up with ACCELERATION `4.9 m//s^(2) , T_(1) =m(9.8 + 4.9)` When mass is LOWERED with same acceleration, `T_(2) =m(9.8 - 4.9)` `therefore T_(1)/T_(2) = 14.7/4.9 = 3:1` |
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