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A mass of 2 kg tied to a string 1 m length is rotate in a verticle circle with a uniform speed of `4 m//s`. The tension in the string will be 52 N, when the mass is at `(g=10 m//s^(2))`A. bottomB. highest pointC. midwayD. horizontal position |
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Answer» Correct Answer - A `T=(mv^(2))/(r)+m g cos theta ` `therefore mg cos theta =T-(mv^(2))/(r)` `=52-(2xx16)/(1)` ` cos theta =(20)/(mg)=(20)/(2xx10)=1` `cos theta =1` `theta =cos^(-1) (0)=0`. |
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