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A mass of `5kg` is moving along a circular path or radius `1m`. If the mass moves with 300 revolutions per minute, its kinetic energy would beA. `250pi^(2)`B. `100pi^(2)`C. `5pi^(2)`D. 0 |
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Answer» (a) Given, mass=m=5kg Radius=1m=R Revolution per minute `omega=300"rev/min"` `(300xx2pi)"rad/min"` `=(300xx2xx314)"rad/60s"` `(300xx2xx3.14)/(60)"rad/s"=10pi"rad/s"` linear speed=v=`omegaR` `((300xx2pi)/(60))(1)=10pim//s` `KE=(1)/(2)xx5xx(10pi)^(2)` `100pi^(2)xx5xx(1)/(2)` `=250pi^(2)J` |
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