InterviewSolution
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InterviewSolution
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A mass of `5kg` is moving along a circular path or radius `1m`. If the mass moves with 300 revolutions per minute, its kinetic energy would beA. `250pi^2 J`B. `100 pi^2 J`C. `5pi^2 J`D. 0 J |
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Answer» Correct Answer - A Here, Mass, m=5 kg, Radius ,R=1 m `upsilon`=300 rpm =`300/60` rps = 5 rps The angular speed is given by `omega=2piupsilon =2pixx5=10 pi "rad" s^(-1)` The linear speed is `v=omegaR=(10pi s^(-1)) (1 m) = 10 pi m s^(-1)` Kinetic energy, `K=1/2mv^2` `K=1/2xx(5 kg) (10 pi m s^(-1))^2 =250pi^2 J` |
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