A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would beA. 20 atmB. 66.28 atmC. 30 atmD. 150 atm

A mass of dry air at NTP is compressed to (1)/(20)th of its original v

1.	A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would beA. 20 atmB. 66.28 atmC. 30 atmD. 150 atm
Answer» Correct Answer - B From `p_(2)V_(2)^(gamma)=p_(1)V_(1)^(gamma)` `rArr" " p_(2)=P_(1)((V_(1))/(V_(2)^(gamma)))^(gamma)=1((V_(1))/(1//20V_(1)))^(1.4)` =66.28 atm

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A mass of dry air at NTP is compressed to (1)/(20)th of its original volume suddenly . If `gamma=1.4` , the final pressure would beA. 20 atmB. 66.28 atmC. 30 atmD. 150 atm

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