1.

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45^(@) with the initial vertical direction is :

Answer»

`MG(SQRT2+1)`
Mg
`(Mg)/sqrt2`
`Mg(sqrt2-1)`

SOLUTION :In equilibrium
`T sin 45^(@) = F`

`T cos 45^(@)=mg`
`:.TAN 45^(@)=(F)/(mg)`
`impliesF=mg`
Here choice is (b)


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