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InterviewSolution
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A maximum current of 0.5 mA can be passed through a galvometer of resitanced 20 Omega. Calculate the resitance to be connected in series to convert it into a voltmeter of range0 - 5V . |
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Answer» Solution :`R = G(n-1) , " where " n = (V_2)/(V_1)` `V_2 = 5 V , V_1 = i G = 0.5 xx 10^(-3) xx 20 = 10^(-2) V` `THEREFORE n = 500` and R = 20 (500 -1) `= 9980 Omega` |
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