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InterviewSolution
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A metal ball having a diameter of `0.4` m is heated from `273` to `360 K.` If the coefficient of areal expansion of the material of the ball is `0.000034 K^(-1)`, then determine the increase in surface area of the ball. |
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Answer» Given, dimeter =`0.4` m and radius, `r=(0.4)/(2)=0.2` m `therefore " " ` Area of ball `A_(o)=4pir^(2)=4xxpixx(0.2)^(2)=0.5024 m^(2)` Temperature, `DeltaT=T_(2)-T_(1)-T_(1)=360K-273K=87K` Coefficient of area expansion, `beta=0.000034K^(-1)` Apply `DeltaA=betaA_(o)DeltaT` `Rightarrow" " DeltaA=0.000034xx0.5024xx0.5024xx87=0.001486=1.486xx10^(3)m^(2)` |
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