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A metal ball of mass 2 kg moving with a velocity of 36 km./h has a head on collision with a stationary ball of mass 3 kg. If after the collision the two balls move together, the loss in K.E. due to collision is : |
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Answer» 140 J `m_(1)v_(1)+m_(2)v_(2)=(m_(1)+m_(2))V` `implies 2xx10+0-(2+3)vimpliesv=4 m//s` `:.` LOSS in K.E. = INITIAL K.E. - Final K.E. =`1/2m_(1)u^(2)-1/2(m_(1)+m_(2))v^(2)` =`1/2xx2xx100-1/2xx5xx16=100-40=60 J`. |
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