1.

A metal complex Cr(NH_(3))_(4)Cl_(2) having molar conductivity corresponding to 1:1 electrolyte have been isolated in two Forms (X) and (Y), (X) reacts with AgNO_(3) giving white precipitate which turns yellow on reaction with sodium arsenite whereas (Y) gives a yellow precipitate soluble in concentrate NH_(4)OH The correct formula and the IUPAC name of the complex (X) is :

Answer»

`[Cr(NH_(3))_(4)Cl_(2)]Br` and tetraaminedichloridochromate(II) BROMIDE.
`[Cr(NH_(3))_(4)ClBr]CL` and tetraamminebromidochloridochromate(II) chloride.
`[Cr(NH_(3))_(4)ClBr]Cl` and tetramminebromidochloridochromium(III) chloride.
`[Cr(NH_(3))_(4)ClBr]Cl` and tetraamminebromidochloridochromium(III) chloride.

Solution :`underset(d^(3))(X) to underset(d^(2)sp^(3))[Cr(NH_(3))_(4)ClBr]Cl,(Y) to underset(d^(2)sp^(3),mu=3.8 B.M.)[Cr(NH_(3))_(4)Cl_(2)]Br`
`"EAN" to 24-3+12=33`
Both X and Y can show G.I.


Discussion

No Comment Found