1.

A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth's magnetic field is 0.2xx10^(-4)T, then the e.m.f. developed between the two ends of the conductor is

Answer»

`5 mu V`
`50 m V`
`5 mV`
`50 mu V`

Solution :INDUCED e.m.f. `=(1)/(2) B omega l^(2)=(1)/(2)XX(0.2xx10^(-4))xx5xx(1)^(2)`
`THEREFORE`Induced e.m.f. `=5xx10^(-5)=50 mu V`


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