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A metal conductor of length 1 m rotates vertically about one of its ends at a constant angular velocity of 5 rad s^(-1) If the horizontal component of earth's magnetic field is 0.4 xx 10^(-4) T, the emf developed between the two ends of the conductor is |
| Answer» Solution :Induced emf `=1/2Blomega^(2)=1/2 xx 0.4 xx 10^(-4) xx 1 xx (5)^(2)=5 xx 10^(-5)V=50muV` | |