A metal (M)and a non - metal (X) form a compound withformula M_(4)X_(3). Predict the electronic arrangements of M and X assuming that M has three occupied shells and X has two occupied shells. Also derive the formulae of (a)sulphate (b)dihydrogen phosphate ( c) hydroxide of ion of M.

A metal (M)and a non - metal (X) form a compound withformula M_(4)X_(3

1.	A metal (M)and a non - metal (X) form a compound withformula M_(4)X_(3). Predict the electronic arrangements of M and X assuming that M has three occupied shells and X has two occupied shells. Also derive the formulae of (a)sulphate (b)dihydrogen phosphate ( c) hydroxide of ion of M.
Answer» SOLUTION :Formula`M_(4)X_(3)`corresponds to`M^(+3)X^(-4)`.M has THREE occupied SHELLS K, Land M . Thenumber of electrons in valece shell is equal to 3. theelectronic arrangement could be 2 , 8 , 3 which corresponds to Z = 13 that is aluminium . X has two occupied shells K and L and L shell must have 4 electrons . theelectronic arrangement could be 2 , 4which corresponds to Z = 6 thatis carbon. (a)`{:(Al^(+3)SO_(4)^(-2),),(Al_(2)(SO_(4))_(3),):}` (b)`{:(Al^(+3)H_(2)PO_(4)^(-),),(Al(H_(2)PO_(4))_(3),):}` (c )`{:( Al^(+3)OH^(-),),(Al(OH)_(3),):}`