1.

A metal M of equivalent mass E forms an oxide of molecular formula M_(x)O_(y). The atomic mass of the metal is given by the correct equation

Answer»

`2E(y//X)`
`xy//E`
`E//y`
`y//E`

Solution :If m is the atomic mass of the metal M, then 16 y g of oxygen combine with x m g of the metal.
`therefore"8 g of oxygen will combine with metal"`
`=(xm)/(16Y)XX8=(xm)/(2y)`
` therefore (xm)/(2y)=E"or"m=2E(y//x)`


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