1.

A metal M of equivalent mass E forms an oxide of molecular formula M_(x)O_(y). The atomic mass of the metal is given by the correct equation:

Answer»

2E(x/y)
xyE
E/y
y/E

Solution :Let atomic mass of METAL M is 'a'
Mass of metal =`axx x`
Mass of oxygen=`16xxy`
EQUIVALENT mass of element`=("Mass of element")/("Mass of oxygen")XX8`
`E=(ax)/(16y)xx8`
`a=2E((y)/(x))`


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