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A metal `M` readily forms water soluble `MSO_(4)` water insoluble `M(OH)_(2)` and oxide `MO` which becomes inert on heating. The hydroxide is soluble in `NaOH`. Then `M` is:A. `Be`B. `Mg`C. `Ca`D. `Sr` |
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Answer» Correct Answer - A Given, `M` reacts to give `MSO_(4)`, which is water soluble. `M` reacts to give `M (OH)_(2)`, which is water insoluble. `M` reacts to give `MO`, which becomes inert on heating. `M(OH)_(2)` is soluble in `NaOH`, this indicates that `M` is `Be`, since only `Be`, due to its small size and high ionisation enthalpy, is amphoteric and gives `M(OH)_(2)` which dissolves in `NaOH`. `Be(OH)_(2)+2NaOHrarrNa_(2)BeO_(2)+2H_(2)O` other facts given are true for `Be` and not for others. |
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