A compound `(A)` on heating in Busen flame imparts brick red colouration. `(A)` on heating gives `CO_(2)` gas and a residue `(B)`. The residue `(B)` when treated with water gives `(c )`. On passing an excess of `CO_(2)` through `(C )` in water, a clear solution `(D)` is obtained. On boiling `(D)`, compound `(A)` is reformed. Residue `(B)` isA. `CaO`B. `CaO_(2)`C. `SrO`D. `BaO`

A compound `(A)` on heating in Busen flame imparts brick red colourati

1.	A compound `(A)` on heating in Busen flame imparts brick red colouration. `(A)` on heating gives `CO_(2)` gas and a residue `(B)`. The residue `(B)` when treated with water gives `(c )`. On passing an excess of `CO_(2)` through `(C )` in water, a clear solution `(D)` is obtained. On boiling `(D)`, compound `(A)` is reformed. Residue `(B)` isA. `CaO`B. `CaO_(2)`C. `SrO`D. `BaO`
Answer» Correct Answer - A Compound `(A)` imparts brick red colouration to the Bunsen flame, hence element present in it is `Ca`. On heating `(A),CO_(2)` is evolved, hence `(A)` is `CaCO_(3)`. `underset((A))(CaCO_(3))overset(Delta)rarrunderset("Residue")underset((B))(CaO)+CO_(2)uarr.("Residue"(B)is CaO)` `underset((B))(CaO)+H_(2)Orarrunderset((C))(Ca(OH)_(2)) [(C) is Ca(OH)_(2)]` `Ca(OH)_(2) +H_(2)O +underset("Excess")(CO_(2)) rarr underset((D))(Ca(HCO_(3))_(2)` `underset((D))(Ca(HCO_(3))_(2) overset(Delta)rarr underset((A))(CaCO_(3) +H_(2)O +CO_(2)`

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For two ionic solids, `CaO` and `KI`, which of the following statements is false?A. Lattice enthalpy of `CaO` is much higher than that of `KI`.B. `CaO` has high melting point.C. `KI` has low melting point.D. `KI` is soluble in benzene.
As the nuclear charge increases from neon to calcium, the orbital energiesA. IncreaseB. Increases very rapidlyC. increases very slowlyD. Fall
A compound `(A)` on heating in Busen flame imparts brick red colouration. `(A)` on heating gives `CO_(2)` gas and a residue `(B)`. The residue `(B)` when treated with water gives `(c )`. On passing an excess of `CO_(2)` through `(C )` in water, a clear solution `(D)` is obtained. On boiling `(D)`, compound `(A)` is reformed. Residue `(B)` isA. `CaO`B. `CaO_(2)`C. `SrO`D. `BaO`
A metal `M` readily forms water soluble `MSO_(4)` water insoluble `M(OH)_(2)` and oxide `MO` which becomes inert on heating. The hydroxide is soluble in `NaOH`. Then `M` is:A. `Be`B. `Mg`C. `Ca`D. `Sr`
Two metals `(A)` and `(B)` belong to the same group of the periodic table. Metal `(A)` forms and insoluble oxide but a soluble sulphate, metal `(B)` forms a soluble oxide but an insoluble oxide but an insoluble sulphate. Both metals `(A)` and `(B)` form hydroxides which are soluble in alkalis. `(A)` and `(B)` areA. `Ba` and `Mg`B. `Na` and `K`C. `Mg` and `Ba`D. `K` and `Rb`
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`CaC_(2)` reacts with water to giveA. MethaneB. EthaneC. EthyleneD. Acetylene
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