1.

A metal M with specific heat (0.16) have chlorine 68.3% then the formula of the compound is similar to

Answer»

MCl
`MCl_(2)`
`MCl_(3)`
`MCl_(4)`

Solution :MASS of CHLORINE in the metal chloride = 68.3% Mass of metal = 100-68.3 = 31.7
Equivalent mass of the metal `=("mass of metal")/("mass of chlorine") xx 35.5`
`=31.7/68.3 xx 35.5 = 16.47`
According to Dulong and Petit.s LAW,
Approx, atomic mass of the metal `=6.4/(0.16) = 40`
VALENCY `=("Approximation atomic mass")/("Equivalent mass") = 40/16.47 = 2.42 =2`
Hence, the formula of the compound = `MCl_(2)`


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