1.

A metal of work function 4eV is exposed to a radiation of wavelength 140xx10^(-9) m. Find the stopping potential developed by it.

Answer»

Solution :`E=(HC)/(lamda)`
`E=(6.62xx10^(-34)xx3xx10^(8))/(140xx10^(-9)xx1.6xx10^(-19))eV=8.86eV`
work function `W_(0)=4eV`
`eV_(0)=E-W_(0)=8.86-4=4.86V`
`:.` Stopping POTENTIAL `V_(0)=4.86V`


Discussion

No Comment Found

Related InterviewSolutions