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A metal of work function 4eV is exposed to a radiation of wavelength 140xx10^(-9) m. Find the stopping potential developed by it. |
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Answer» Solution :`E=(HC)/(lamda)` `E=(6.62xx10^(-34)xx3xx10^(8))/(140xx10^(-9)xx1.6xx10^(-19))eV=8.86eV` work function `W_(0)=4eV` `eV_(0)=E-W_(0)=8.86-4=4.86V` `:.` Stopping POTENTIAL `V_(0)=4.86V` |
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