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A metal parallel plate capacitor has 100mm diameter and the distance between the plates is 1mm. The capacitor is placed in air. Calculate the potential difference between the plates if the force on each plate is 0.035N.(a) 1kV(b) 1V(c) 2kV(d) 2VI got this question during an online interview.My question is based upon Force of Attraction Between Oppositely Charged Plates topic in division Capacitance and Capacitors of Basic Electrical Engineering

Answer»

The CORRECT answer is (a) 1kV

Explanation: From the given DATA:

A=pi*d^2/4=0.007854m^2

Potential gradient = V/x = 1000*V

F=epsilon*A*(V/x)^2/2

Substituting the given VALUES in the above EXPRESSION, we get V=1kV.



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